When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
other example:
When
a≠0
,
there are two solutions to
ax2
+ bx
+ c = 0
and they are
x =
−
b
±
b2
−
4ac
2a
.
When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
other example:
When
a≠0
,
there are two solutions to
ax2
+ bx
+ c = 0
and they are
x =
−
b
±
b2
−
4ac
2a
.